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sinα-cosα=1/3,则cos4α=?
人气:426 ℃ 时间:2020-06-28 10:35:44
解答
sinα-cosα=1/3(sinα-cosα)^2=1/9(sinα)^2+(cosα)^2-2sinαcosα=1/91-2sinαcosα=1/92sinαcosα=8/9sin2α=8/9cos2α=±√17/9cos4α=(cos2α)^2-(sin2α)^2=17/81-64/81=-47/81
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