由题意可知：x≠14且x≠13,x≠9,x≠11,那么：原方程可化为：5/(x-11)-5/(x-13)=2/(x-9)-2/(x-14)通分得：5(x-13-x+11)/[(x-11)(x-13)]=2(x-14-x+9)/[(x-9)(x-14)]-10/[(x-11)(x-13)]=-10/[(x-9)(x-14)]即(x-9)(x-14)...