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数学
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lim x趋于0[(tanx-sinx)/sinx^3]的极限
人气:129 ℃ 时间:2019-10-17 00:43:06
解答
=lim(1/cosx-1)/(sinx)^2
=lim(1-cosx)/(sinx)^2cosx
=lim2(sin(x/2))^2/(sinx)^2
=(1/2)lim[(sin(x/2))^2/(x/2)^2][x^2/(sinx)^2]
=1/2
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