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两圆c1:x^2+y^2+2x+2y -8=0,C2:x^2+y^2-2x+10y-24=0相交于两点A,B,求经过A,B两点且面积最小的圆的方程
人气:370 ℃ 时间:2019-09-09 18:29:58
解答
x^2+y^2+2x+2y -8=0·······················ax^2+y^2-2x+10y-24=0·····················ba,b两式相减得:x=2y-4······················c将c式代...
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