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tan675°+cos765°-sin(-5/2 π)+sec(-23/6 π)=?
人气:446 ℃ 时间:2020-07-27 08:19:24
解答
tan675°+cos765°-sin(-5π/2)+sec(-23π/6)
=tan(675°-720°)+cos(765°-720°)-sin(4π-5π/2)+sec(4π-23π/6)
=tan(-45°)+cos45°-sin(3π/2)+secπ/6
=-1+√2/2+1+2√3/3
=2√3/3+√2/2
cosα*secα=1
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