∵abc≠0,∴p≠0
1/p = (a+b)/c = (b+c)/a = (c+a)/b
∴a+b = c/p,b+c=a/p,c+a=b/p
∴2(a+b+c) = (a+b+c)/p,∴p = 1/2>0
∴y过一、二、三象限