99…9(1000个9)×99…9(1000个9)+199…9(1000个9)=?
根号下99…9(n个9)×99…9(n个9)+199…9(n个9)=?
人气:127 ℃ 时间:2019-08-22 14:52:51
解答
√[99…9(n个9)×99…9(n个9)+199…9(n个9)]
=√{[99…9(n个9)]^2+2*[99…9(n个9)]+1}
=√{[99…9(n个9)+1]^2}
=√{[100...0(n个0)]^2}
=√[(10^n)^2]
=10^n.
99…9(1000个9)×99…9(1000个9)+199…9(1000个9)
=[99…9(1000个9)]^2+2*99…9(1000个9)+1
=[99…9(1000个9)+1]^2
=[100...0(1000个0)]^2
=(10^1000)^2
=10^2000.
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