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计算:
(1)(−
3
2
x2y)2(2x2−4xy+7y2)

(2)(-4x-3y2)(3y2-4x)
人气:214 ℃ 时间:2020-04-10 10:05:45
解答
(1)原式=
9
4
x4y2
(2x2-4xy+7y2),
=
9
2
x6y2−9x5y3+
63
4
x4y4

(2)原式=(-4x-3y2)(-4x+3y2),
=(-4x)2-(3y22
=16x2-9y4
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