恒等变换中的话,推荐这道题求(tan10°-根号3)*cos10°/sin50°的值(tan10°-√3)*cos10°/sin50°=(sin10°-√3cos10°)/sin50°=2(1/2*sin10°-√3/2*cos10°)/sin50°=2(sin10°cos60°cos10°sin60°)/sin50°=2s...