1
f(x)=-(cosωx)^2+(√3) *sin2ωx
=-1/2 -cos2ωx+(√3)*sin2ωx
=-1/2-2*[cosπ/3cos2ωx -sinπ/3sin2ωx]
=-1/2-2*cos(π/3+2ωx)
π/3+2ωx=(2k+1)π时,f(x)最大f(x)=3/2,其中K是整数
x=2π/3,ω=(6k+2)/(4
=（3k+1）/2
k=1时,ω最小正整数2,
f(x)=-1/2-2cos[(π/3)+4x]
2.x=0时,f(x)=-1
x=π/6时,f(x)=1/2
x=π/3时,f(x)=-1
在(0,π/6）,f(x)单调上升,（π/6,π/3],f(x)单调下降,
x∈(0,π/3],y=f(x)值域,-1 ≤f(x)≤1/2