这么简单都不会...
（A+B）^2
=A^2+B^2+AB
=2+cos(3x/2)cos(x/2)-sin(3x/2)sin(x/2)
=2+cos(3x/2-x/2)
=2+cosx
|A+B|
=根号（A+B）^2
=根号(2+cosx)
2+cosx>=0肯定嘛
X属于[派/2,3/2派]
-1<=cosx<=0
1<=2+cosx<=2
所以|A+B|的范围为[1,根号2]