> 数学 >
求不定积分 ∫√x(x-3 )dx,
人气:247 ℃ 时间:2020-04-07 18:21:22
解答
答:
∫ √x(x-3) dx
=∫ x^(3/2)-3x^(1/2) dx
=(2/5)x^(5/2)-3*(2/3)x^(3/2)+C
=0.4x^(5/2)-2x^(3/2)+C
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版