f'(x)=[xlnx/(x-1) -2ln(1+√x)]'=[xlnx/(x-1)]' -[2ln(1+√x)]'=[(x-1)(xlnx)'-(xlnx)(x-1)']/(x-1)²-2(1+√x)'/(1+√x)=[(x-1)(1+lnx)-xlnx]/(x-1)²-2(1/(2√x))/(1+√x)=(x-1-lnx)/(x-1)²-1/(x+√...