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数学
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求lim为2的n次方+3的n次方分之2的n+1次方+3的n+1次方=3,求极限
人气:447 ℃ 时间:2019-12-14 17:21:00
解答
上下除以3^n
=lim[(2/3)^n+1]/[2*(2/3)^n+3]
(2/3)^n趋于0
所以原式=(0+1)/(0+3)=1/3
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