1f（x）=2√3sinxcosx+2cos2x-1=√3sin2x+cos2x=2sin(2x+π/6)最小正周期T=2π/2=π∵x∈[0,π/2]∴2x+π/6∈[π/6,7π/6]∴2x+π/6=π/2时,f(x)max=22x+π/6=7π/6时,f(x)min=-12 f(x0)=6/5 ,即 2sin(2x0+π/6)=6/5...