延长AE到F,使EF=AE,连接DF∵AE是△ABD的中线∴BE=ED在△ABE与△FDE中BE=DE∠AEB=∠DEF（对顶角相等）AE=EF∴△ABE≌△FDE（SAS）∴AB=DF,∠BAE=∠EFD∵∠ADB是△ADC的外角∴∠DAC=∠ACD=∠ADB=∠BAD∴∠BAE+∠EAD=∠...