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数学
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已知sina-cosa=1/5,0≤a≤π,求sin(2a-π/4)的值
人气:393 ℃ 时间:2020-03-28 09:03:07
解答
(sina-cosa)^2=1/25
sin^2a+cos^2a-2sinacosa=1/25
Sin^2a+cos^2a=1
sinacosa=12/25
消去sina或cosa可解二元一次方程求得:
(0≤a≤π)
Sina=4/5cosa=3/5
Sin(2a-π/4)=√2/2(sin2a-cos2a)=31√2/50
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