已知,如图,E是▱ABCD的边AD上一点,且
=,CE交BD于点F,BF=15cm,求DF的长.

人气:435 ℃ 时间:2019-08-18 12:24:24
解答
∵四边形ABCD是平行四边形,点E在边AD上∴DE∥BC,且AD=BC,∴∠DEF=∠BCF;∠EDF=∠CBF(2分)∴△EDF∽△CBF(3分)∴BCED=BFDF(4分)∵AEDE=32∴设AE=3k,DE=2k,则AD=BC=5k(5分)BCED=BFDF=52(6分)∵BF=...
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