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化简,求值(x-y/x+2y)/(x^2-y^2/x^2+4xy+4y^2)-2.其中x=2+√5,y=2-√5
人气:279 ℃ 时间:2020-05-19 01:38:48
解答
(x-y/x+2y)/(x^2-y^2/x^2+4xy+4y^2)-2
=(x-y/x+2y)/[(x-y)(x+y)/(x+2y)^2]-2
=(x+2y)/(x+y)-2
=-x/(x+y)
=-(2+√5)/4
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