化简函数f(x)=sin2x+根号3（cos2x+1)-根号3
=sin2x+根号3cos2x
=2sin(2x+π/3）即最小正周期为π
2x+π/3属于-π/2+2kπ到π/2+2kπ递增,解出,x属于-5/12π+kπ到1/12π+kπ递增