∵f(13)＝sin(13π/6)＝sin(2π＋π/6)＝sin(π/6)＝f(1) ∴f(1)＝f(1＋12×k)∵f(7)＝sin(7π/6)＝sin(π＋π/6)＝﹣sin(π/6)＝﹣f(1) ∴f(1)＋f(1＋6m)＝0∴f(1)+f(2)+……+f(100)＝8×[f(1)＋f(2)＋•̶...