y=f(x+1)的定义域为[-2,3]
即其中的x满足-2<=x<=3
所以-1<=x+1<=4
所以f(x)定义域是[-1,4]
所以f(2x-1)中2x-1满足-1<=2x-1<=4
0<=2x<=5
0<=x<=5/2
所以f(2x-1)的定义域为[0,5/2]