设x^4-x^3+4x^2+3x+5=(x^2+ax+1)(x^2+bx+5) =x^4+(a+b)x^3+(ab+b)x^2+(5a+b)x+5 根据对应项系数相等,得a+b=-1 ①ab+b=4 ②5a+b=3 ③由①③得a=1,b=-2代入②中,成立∴x^4-x^3+4x^2+3x+5=(x^2+x+1)(x^2-2x+5)...