> 数学 >
把(2z²-2x²-2y²)²-16x²y²因式分解
人气:170 ℃ 时间:2020-06-24 08:57:52
解答
原式=(2z²-2x²-2y²+4xy)(2z²-2x²-2y²-4xy)
=4[z²-(x²-2xy+y²)][z²-(x²+2xy+y²)]
=4[z²-(x-y)²][z²-(x+y)²]
=4(z+x-y)(z-x+y)(z-x-y)(z+x+y)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版