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已知二次函数f(x)满足f(1+1/x)=1/x+x²+1/x²,求f(x)的解析式
人气:133 ℃ 时间:2020-06-15 21:29:23
解答
令t=1+1/x则1/x=t-1 x=1/(t-1)f(1+1/x)=1/x+x²+1/x²=t-1+1/(t-1)²+(t-1)²=t²-t+1/(t-1)²t和x同样在定义域上取值,将t换成xf(x)=x²-x+1/(x-1)²
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