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数学
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若x1,x2是方程x2+2x-2007=0的两个根,求1/x1+1/x2
人气:213 ℃ 时间:2020-04-05 18:31:22
解答
由韦达定理得
x1+x2=-2
x1x2=2007
1/x1+1/x2
=(x1+x2)/(x1x2)
=(-2)/2007
=-2/2007
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