答案是(-∞,0]或[1,3]或[10,+∞)要使[(x-3)(10-x)]/x^2(x-1)≥0则(x-3)(10-x)与x^2(x-1)同时小于等于0或者同时大于等于0令它们同时小于等于0时,无解.所以只会是同时大于等于0(x-3)(10-x)大于等于0,解得x小于等于3或...