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数学
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m^2-4mn+4n^2-3(m-2n)+2
人气:454 ℃ 时间:2020-05-22 21:09:13
解答
原式=(m-2n)²-3(m-2n)+2
=(m-2n-1)(m-2n-2)
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若m=2n+1求m^2-4mn+4n^2的值
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2n^-m/2mn-4n^3
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