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在三角形ABC中 角C+角A=2角B 角C-角A=80度,求角A角B角C
人气:443 ℃ 时间:2019-12-08 07:08:30
解答
c + a = 2b
c - a = 80
-->c = a+80,带入1
--> a + 80 + a = 2b a + 40 = b
a + b + c =180
== a +80 + a + 40 + a =180 ---a = 20,b = 60 c =100
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