解方程5x²-7x-6=0
（5x+3)(x-2）=0
解得x=-3/5,或x=2
∵sinα是方程5x²-7x-6=0的根,sinα∈[-1,1]
∴sinα=-3/5
∴cosα=±4/5,tanα=±3/4
∴[cos(2π-α)cos(π+α)tan²(2π-α)]/[sin(π-α)sin(2π-α)cot(π-α)]
=[cosα(-cosα)tan²α]/[sinα(-sinα)(-cotα)]
=(-cos²α*sin²α/cos²α)/(sin²α*cosα/sinα)
=(-sin²α)/(sinα*cosα)
=-sinα/cosα
=-tanα
=3/4 或-3/4