(1)f(x)=【1-sin(x-3π/2)+cos(x+π/2)+tan3π/4】/cosx=【1-sin(x+π/2)+cos(x+π/2)-1】/cosx=[-cos(-x)+sin(-x)]/cosx=(1-cosx-sinx-1)/cosx=(-cosx-sinx)/cosx求函数y=f(x)的定义域cosx≠0 ,x≠2kπ+π/2（2）设...