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先化简,再求值 (a+1)(a^2-2a-3)+(a-1)(a^2-2)-(2a^2-1)(a+1),其中a=-1
人气:239 ℃ 时间:2020-01-28 04:18:02
解答
(a+1)(a^2-2a-3)+(a-1)(a^2-2)-(2a^2-1)(a+1),
=(a+1)[(a²-2a-3)-(2a²-1)]+(a-1)(a²-2)
=(a+1)(-a²-2a-2)+a³-2a-a²+2
=-a³-2a²-2a-a²-2a-2+a³-2a-a²+2
=-4a²-6a
=-4×(-1)²-6×(-1)
=-4+6
=2
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