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计算[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
如题
人气:162 ℃ 时间:2019-09-09 18:35:39
解答
[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
=(x^3y^2-x^2y-x^2y+x^3y^2)/3x^2y
=(2x^3y^2-2x^2y)/3x^2y
=2x^3y^2/3x^2y-2x^2y/3x^2y
=(2xy-2)/3
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