有两个相等的实数根则判别式等于0[-(m+2)]²-8(2m-2)=0m²+4m+4-16m+16=0m²-12m+20=0(m-2)(m-10)=0m=2,m=10m=2,方程是2x²-4x+2=0,2(x-1)²=0,x=1m=10,方程是2x²-12x+18=0,2(x-3)²=0...