已知a,b,c,是△ABC的三边且满足关系式a²+c²=2ab+2bc-2b²,试判断三角形的形状
人气：407 ℃ 时间：2019-10-18 15:23:30
解答
a²+c²=2ab+2bc-2b²a²+2b²+c²-2ab-2bc=0(a²-2ab+b²)+(b²-2bc+c²)=0(a-b)²+(b-c)²=0因此,a-b=0,且 b-c=0则 a=b=c三角形ABC是等边三角形
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