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求y=arctan(x+1/x-1)的导数
人气:409 ℃ 时间:2020-05-09 10:48:55
解答
y=arctan(x+1)/(x-1)
y'=1/[1+(x+1)^2/(x-1)^2]*[(x+1)/(x-1)]'
=1/[1+(x+1)^2/(x-1)^2]*[(x-1)-(x+1)]/(x-1)^2
=-2/[(x+1)^2+(x-1)^2]
=-1/(x^2+1)
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