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数学
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求导f(x)=-a√(x^2+1)
人气:494 ℃ 时间:2020-01-25 23:28:18
解答
f(x)=-a√(x^2+1)
=-a(x^2+1)^(1/2)
f'(x)=-a*(-1/2)(x^2+1)^(1/2-1)*(x^2)'
=a/2*(x^2+1)^(-1/2)*2x
=2x/√(x^2+1)
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