> 数学 >
求导f(x)=-a√(x^2+1)
人气:357 ℃ 时间:2020-01-25 23:28:18
解答
f(x)=-a√(x^2+1)
=-a(x^2+1)^(1/2)
f'(x)=-a*(-1/2)(x^2+1)^(1/2-1)*(x^2)'
=a/2*(x^2+1)^(-1/2)*2x
=2x/√(x^2+1)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版