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3x^3-x=1,求6x^3+7x^2-5x+29.十万火急~
人气:489 ℃ 时间:2020-04-13 14:05:03
解答
3x^3-x=1
=6x^3+7x^2-5x+29
=(6x^3-2x)+7x^2-3x+29
=2(3x^3-x)+7x^2-3x+29
=7x^2-3x+29+2
=7x^2-3x+31
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