设甲每天做x个零件,乙每天做y个零件,则
10x+16(x+y)=2200 (1)
10y+18(x+y)=2200 (2)
(1)-(2),得8x=12y,即x=3y/2 (3)
把(3)代入(1)解得,y=40,
则x=3×40÷2=60
答：甲每天做60个零件,乙每天做40个零件.