1、0.3（y-2)=1-(x+1)÷5
0.3y-0.6=1-x÷5+0.2
0.3y=1+0.6-x÷5+0.2
0.3y=1.6+0.2-x÷5
0.3y=1.8-x÷5
y=1.8-x÷5÷0.3
y=1.8-x÷1.5
y-1.8=－x÷1.5
y+x=1.8÷1.5
y=2
x=4