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化简 (2*cos10-sin20)/cos20
人气:456 ℃ 时间:2020-02-06 04:50:10
解答
(2cos10-sin20)/cos20
=[2cos10-sin(30-10)]/cos20
=(2cos10-sin30*cos10+sin10cos30)/cos20
=(2cos10-1/2*cos10+√3/2*sin10)/cos20
=(3/2*cos10+√3/2*sin10)/cos20
=√3(√3/2*cos10+1/2*sin10)/cos20
=√3(cos30cos10+sin30sin10)/cos20
=√3cos(30-10)/cos20
=√3cos20/cos20
=√3
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