(2004²+3×2000+12)÷(2004³-2004×9)
=(2004²+3×2004)÷[2004×(2004²-9)]
=[2004×(2004+3)]÷[2004×(2004+3)×(2004-3)]
=1/(2004-3)
=1/2001请问：1/2+2/4+3/8+4/16+……+13/8192这题该怎么解？1/2+2/4+3/8+4/16+……+13/8192=1/2+1/2+3072/8192+2048/8192+1280/8192+768/8192+448/8192+256/8192+144/8192+81/8192+44/8192+24/8192+13/8192=2又85/8192