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sinx+siny=2/3 求cosx+cosy的取值范围
人气:170 ℃ 时间:2020-03-02 21:26:50
解答
sinx+siny=2/3
两边平方得
sin²x+2sinxsiny+sin²y=4/9-----(*)
令t=cosx+cosy
t²=cos²x+2cosx+cos²y
与(*)相加得
t²+4/9=(sin²x+cos²x)+2(sinxsiny+cosxcosy)+(sin²y+cos²y)
t²+4/9=1+2cos(x-y)+1
t²=(14/9)+2cos(x-y)
因为-1=
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