设cosx+cosy=tsinx+siny=√2/2 两个式子分别平方得cos²x+cos²y+2cosxcosy=t²sin²x+sin²y+2sinxsiny=1/2两个式子相加1+1+2cosxcosy+2sinxsiny=t²+1/2cosxcosy+sinxsiny=(t²-3/2)/...