(x-m-3)^2+(y-1+4m^2)^2=(m+3)^2+(1-4m^2)^2-16m^4-9
(x-m-3)^2+(y-1+4m^2)^2=-7m^2+6m+1
(x-m-3)^2+(y-1+4m^2)^2=-(7m+1)(m-1)
表示圆的话,则半径r>0
因此有-(7m+1)(m-1)>0
得-1/7
当m=3/7时,r^2最大,为16/7
即圆面积最大值=16π/7
3)记圆心为(x,y)
则x=m+3
y=1-4m^2
将m=x-3代入后式,得:y=1-4(x-3)^2=-4x^2+24x-35
因为有1/7