由题知,
f(sinx)=2-2cosx,
所以
f(cosx)
=f(sin(π/2-x))
=2-2cos(π/2-x)
=2-2sinx题目打错了，sorry。若f(sinx)=2-cos2x,则f(cosx)等于、、、f(cosx)
=f[sin(π/2-x)]
=2-cox[2(π/2-x)]
=2-cos(π-2x)
=2+cos2x