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数学
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求函数y=(x^4+3x^2+3)/(x^2+1)的最小值
希望利用基本不等式来求
并有详细的过程
谢谢
人气:247 ℃ 时间:2019-09-06 23:54:00
解答
y=[(x^4+x^2)+(2x^2+2)+1]/(x^2+1)
=x^2+2+1/(x^2+1)
=(x^2+1)+1/(x^2+1)+1
≥2根号[(x^2+1)/(x^2+1)+1
=3
所以,函数y=(x^4+3x^2+3)/(x^2+1)的最小值是3
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