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求当x为何值时,代数式6x^2+12x+10/x^2+2x+2可取的最小值,最小值是?
人气:114 ℃ 时间:2020-03-16 19:46:33
解答
6x^2+12x+10/x^2+2x+2
=6(x^2+2x+2)-2/(x^2+2x+2)
=6-2/(x^2+2x+2)
=6-2/[(x+1)^2+1]
(x+1)^2+1>=1
所以0
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