1.
f(x)=sin2xcosφ-2cos²xsin(π-φ)-cos(π/2+φ)
=sin2xcosφ-(cos2x+1)sinφ+sinφ
=sin2xcosφ-cos2xsinφ
=sin(2x-φ)
T=2π/2=π
2.
取最大值时
2x-φ=2kπ+π/2
由于-π/2<φ<π/2
φ=-π/6
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