如图,已知AC⊥BD,AD⊥BD,AD=BC,CE⊥AB,DF⊥AB,垂足分别是E、F.证明:CE=DF
人气:196 ℃ 时间:2020-03-29 17:08:06
解答
∵AC⊥BC,AD⊥BD∴∠ACB=∠BDA=90°在Rt△ACB和Rt△BDA中 AB=BAAD=BC∴Rt△ACB≌Rt△BDA∴∠ABC=∠BAD又∵CE⊥AB,DF⊥AB∴∠AFD=∠BEC=90°在△ADF和△BCE中 ∠BAD=∠CBA∠AFD=∠BECAD=BC∴△ADF≌△BCE∴CE=D...
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